19. February 2009 00:04
This simple user function will return the beginning of the day given a datetime in SQL.
ALTER FUNCTION [dbo].[fnBeginningOfDay](@date DATETIME)
RETURNS DATETIME
AS
BEGIN
DECLARE @finalDate DATETIME
SET @finalDate = (SELECT CAST(DATEPART(mm,@date) AS VARCHAR(5)) + '/' + CAST(DATEPART(dd,@date) AS VARCHAR(5)) + '/' + CAST(DATEPART(yyyy,@date) AS VARCHAR(10)))
RETURN @finalDate
END
You can test it with the following:
SELECT dbo.fnBeginningOfDay('01/02/2009 06:30:00 AM')
SELECT dbo.fnBeginningOfDay(getDate())
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